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2.5x^2-2x=360
We move all terms to the left:
2.5x^2-2x-(360)=0
a = 2.5; b = -2; c = -360;
Δ = b2-4ac
Δ = -22-4·2.5·(-360)
Δ = 3604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3604}=\sqrt{4*901}=\sqrt{4}*\sqrt{901}=2\sqrt{901}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{901}}{2*2.5}=\frac{2-2\sqrt{901}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{901}}{2*2.5}=\frac{2+2\sqrt{901}}{5} $
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